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3 years ago

What is the result of dividing 2x3+x2−2x+8 by x + 2?

Mathematics

2 answers:

Irina-Kira [14]3 years ago

8 0

Answer:

Quotient = $2x^2 - 3x +4$

Remainder = 0

Step-by-step explanation:

Here, the given expression,

${2x^3 + x^2 - 2x + 8}\div {x + 2}$

By the long division, ( shown below )

We get,

$\frac{2x^3 + x^2 - 2x + 8}{x + 2}=(2x^2 - 3x + 4)\times (x+2) +0$

Since,

Dividend = Quotient × Divisor + Remainder

Hence,

Quotient = $2x^2 - 3x +4$

Remainder = 0

OLga [1]3 years ago

6 0

2x^3+x^2-2x+8 / x+2=

2x^2-3x+4

2x3+x2−2x+8 / x + 2=

6x+8 over x+2

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A 2-column table with 3 rows. Column 1 is labeled Number of Rows with entries 1, 3, 5. Column 2 is labeled Number of Seats with

Mnenie [13.5K]

Answer:

Step-by-step explanation:

One row has 6 seats

3 rows have:

3*6 = 18 seats

5 rows have:

5*6 = 30 seats

A = 30

4 0

2 years ago

Read 2 more answers

Help me please with 2 and 3

IRINA_888 [86]

The answer for #2 is A

And the answer for #3 is B

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3 years ago

Read 2 more answers

According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe

Ann [662]

Using the normal distribution and the central limit theorem, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

In this problem:

22% of couples meet online, hence p = 0.22.

A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

$\mu = p = 0.22$

$s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338$

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is one subtracted by the p-value of Z when X = 0.25, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.25 - 0.22}{0.0338}$

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15, hence:

X = 0.2:

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.2 - 0.22}{0.0338}$

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.15 - 0.22}{0.0338}$

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the normal distribution and the central limit theorem, you can check brainly.com/question/24663213

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2 years ago

A box contains 6 red balls, 7 green balls and 5 blue balls. each ball is of different size. the probability that the red ball se

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3 years ago

. Laura and Alicia both exercise 5 days a week. Laura exercises for 30 minutes each day. Alicia exercises for 45 minutes each da

statuscvo [17]

Answer: 1 hour 15 minutes

Step-by-step explanation:

From the question, we are informed that Laura and Alicia both exercise 5 days a week and that Laura exercises for 30 minutes each day. For the 5 days, she'll exercise for:

= 5 × 30 minutes

= 150 minutes

= 2 hours 30 minutes

Alicia exercises for 45 minutes each day. Fir the 5 days, she'll exercise for:

= 5 × 45 minutes

= 225 minutes

= 3 hours 45 minutes

We then calculate the difference in their exercise per week which will be:

= 3 hours 45 minutes - 2 hours 30 minutes

= 1 hour 15 minutes

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3 years ago