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3 years ago

A very small tilt in Earth’s axis would likely cause ____.

Physics

2 answers:

Lesechka [4]3 years ago

6 0

Answer:

A very small tilt in Earth’s axis would likely cause _____.

no climate changes

large seasonal variations in temperature

short-term climate changes

small seasonal variations in temperature

Explanation:

Answer small seasonal variations in temperature

The tilt of Earth’s axis changes by about 3 degrees. This affects the severity of the seasons. When Earth’s axis is less tilted, the temperature difference between summer and winter is less.

blagie [28]3 years ago

3 0

This would result to small changes in temperature and pressure at various focal pints of the earth relative to the tilt angle. The earth is already at a 23.5 degree tilt angle thus change of this angle would trigger extremities of both high and low temperatures in specific regions.

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Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts

wolverine [178]

Answer:

0.304 m/s2

Explanation:

If the first child is pushing with a force of 69N to the right and the 2nd child is pushing with a force of 91N to the left. Then the net pushing force is 91 - 69 = 22 N to the left. Subtracted by 15N friction force then the system of interest is subjected to F = 7 N net force tot he left.

We can use Newton's 2nd law to calculate the net acceleration of the system

$a = F/m = 7 / 23 = 0.304 m/s^2$

5 0

3 years ago

Define distance and displacement with illustration

Deffense [45]

Answer:

<h2>Distance</h2>

The length of the actual path travelled by a body is called distance travelled by a body.It is a scalar Quantity.It is measured in meter(m) in SI system.

<h2>Displacement</h2>

The shortest distance from initial position to the final position of a body is called displacement of the body.It is a vector Quantity.It is measured in meter(m) in SI system..

Please see the attached picture...

It is the example of distance and displacement....

Hope this helps...

Good luck on your assignment...

3 0

3 years ago

Ask Your Teacher A circular wire loop whose radius is 10.0 cm carries a current of 3.60 A. It is placed so that the normal to it

e-lub [12.9K]

Answer:

$M=0.113\ Am^2$

Explanation:

Given that,

Radius of the circular loop, r = 10 cm = 0.1 m

Current flowing in the loop, I = 3.6 A

Uniform magnetic field, B = 12 T

To find,

The magnetic dipole moment of the loop.

Solution,

Let M is the magnitude of magnetic dipole moment of the loop. We know that the product of current flowing and the area of cross section. Its formula is given by :

$M=I\times A$