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Crazy boy [7]
2 years ago
9

What slows down electricity?

Physics
2 answers:
tino4ka555 [31]2 years ago
4 0

Answer:

D

Explanation:

Ivan2 years ago
4 0
Answer : D

Explanation:
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Can a physical quantity have different dimensions in different systems of units?​
Mars2501 [29]
Answer: yes a quantity have different dimensions in different system of units . No,because in different system of units doesn't change the quantity but it only changes the numerical.

Good luck !
4 0
2 years ago
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As a result, the total energy in a ____ system (in other words, a system with no external forces) will remain constant
Alika [10]

Answer:

Isolated or Closed system, both are correct

4 0
2 years ago
If you could go a year into the future, or 3 seconds into the past, where would you go? What date? I would go to June 6th, 2018
vova2212 [387]
Idk I would go back to pre-k
8 0
3 years ago
A 7.5-cmcm-diameter horizontal pipe gradually narrows to 4.5 cmcm . When water flows through this pipe at a certain rate, the ga
tino4ka555 [31]

Answer

given,

diameter,d₁ = 7.5 cm

               d₂ = 4.5 cm

P₁ = 32 kPa

P₂ = 25 kPa

Assuming, we have calculation of flow in the pipe

using continuity equation

 A₁ v₁ = A₂ v₂

 π r₁² v₁ = π r₂² v₂

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{2.25^2}{3.75^2} v_2

 v_1= 0.36 v_2

Applying Bernoulli's equation

 \Delta P = \dfrac{1}{2}\rho (v_2^2-v_1^2)

 P_1-P_2 = \dfrac{1}{2}\rho (v_2^2-(0.36 v_2)^2)

 32-25 = \dfrac{1}{2}1000\times v_2^2 (1 - 0.1269)

 v_2=\sqrt{\dfrac{2\times 7\times 10^3}{1000\times (0.8704)}}

 v_2=\sqrt{16.084}

       v₂ = 4.01 m/s

fluid flow rate

Q = A₂ V₂

Q = π (0.0225)²  x 4.01

Q = 6.38 x 10⁻³ m³/s

flow in the pipe is equal to 6.38 x 10⁻³ m³/s

4 0
3 years ago
As a capacitor is being charged in an RC circuit. the current flowing through a resistor isa) increasingb) decreasingc) constant
Montano1993 [528]
<h2>Answer: decreasing</h2>

An RC circuit is an electrical circuit composed of resistors and capacitors, where the charging time T of the circuit is proportional to the magnitude of the electrical resistance R and the capacity C of the capacitor.  

As shown below:

T=R.C

In this context, the electrical resistance is the opposition to the flow of electrons when moving through a conductor.

Therefore:

<h2>When a capacitor is being charged in an RC circuit, the current flowing through a resistor <u>decreases</u>.</h2>

And the correct option is b.

4 0
2 years ago
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