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Phantasy [73]
2 years ago
6

1000 millicoulombs of charge passes through a point. The amount of current passing through the point is

Physics
1 answer:
Rzqust [24]2 years ago
3 0

The amount of current passing through the point is 1 A

The amount of current passing through the point can be calculated using the formula below.

⇒ Formula:

  • Q = i/t......................... Equation 1

⇒ Where:

  • Q = Charge
  • i = current
  • t = time.

⇒ Make "i" the subject of the equation.

  • i = Qt....................... Equation 2

From the question,

⇒ Given:

  • Q = 1000 millicoulombs = 1 coulombs
  • t = 1 seconds. (Assuming the time is 1 seconds)

⇒ Substitute these values into equation 2

  • i = 1/1
  • i = 1 A.

Hence, The amount of current passing through the point is 1 A.

Learn more about charges here: brainly.com/question/4158552

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Not every lightning strike produces thunder. a. Trueb.False
podryga [215]

Answer: The given statement is false.

Explanation:

Lightening is defined as steady expansion of air within and surrounding path due to the sudden increase in pressure and temperature that leads to emission of lightning.

Basically, lightning is a state of plasma in which the molecules are very rapidly striking with each other as it also contains positively charged ions and negatively charged electrons.

Lightning always leads to the production of thunder.

Therefore, we can conclude that the statement not every lightning strike produces thunder, is false.

7 0
3 years ago
Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two
andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges \rm q_1 and \rm q_2 which are separated by the distance \rm d is given by

\rm F = \dfrac{kq_1q_2}{d^2}.

<em>where,</em> k is the Coulomb's constant.

For the case, when,

  • \rm q_1 = Q.
  • \rm q_2 = Q.
  • \rm d=r.
  • \rm F=12.3442.

Then, using Coulomb's law,

\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).

For the case, when,

  • \rm q_1 = 2Q.
  • \rm q_2 = 2Q.
  • \rm d=\dfrac r2.

Then, using Coulomb's law, the new electric force between the charges is given by,

\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.

8 0
2 years ago
A uniformly accelerating rocket is found to have a velocity of 11.0 m/s when its height is 4.00 m above the ground, and 1.90 s l
aleksklad [387]

Answer:

17.23 m/s²

Explanation:

Applying the equation of motion,

Δs = ut + 1/2at²..................... Equation 1

Where Δs  = change in height of the rocket, u = initial velocity of the rocket, a = acceleration of the rocket, t = time

making a the subject of the equation,

a = 2(Δs-ut)/t²..................... Equation 2

Given: Δs = (56-4) m = 52 m, u = 11.0 m/s, t = 1.90 s.

Substitute into equation 2

a = 2[52-(11×1.9)]/1.9²

a = 2(52-20.9)/1.9²

a = 2(31.1)/3.61

a = 62.2/3.61

a = 17.23 m/s².

Thus the acceleration = 17.23 m/s²

5 0
3 years ago
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