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AURORKA [14]
3 years ago
6

A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationary seal of m

ass 200 kg. The seal grabs onto the whale and holds fast. What is the momentum of these two sea creatures just after their collision
Physics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

Momentum after collision will be 6000 kgm/sec

Explanation:

We have given mass of the whale = 1000

Initial velocity v = 6 m/sec

It collides with other mass of 200 kg which is at stationary

Initial momentum of the whale = 1000×6 = 6000 kgm/sec

We have to find the momentum after collision

From conservation of momentum

Initial momentum = final momentum

So final momentum = 6000 kgm/sec

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Which of the following is not a source of light? *<br> a) sun<br> b) star<br> c) mirror<br> d)cfl
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I think that would be c) mirror because mirrors reflects light and can't create it.

5 0
3 years ago
amping equipment weighing 6.0 kN is pulled across a frozen lake by means of ahorizontal rope. The coecient of kinetic friction i
Harman [31]

Answer:

Work done = 422.45 kJ

Explanation:

given,                                  

weight of equipment = 6 kN      

coefficient of kinetic friction = 0.05          

distance up to which it is pulled = 1000 m

constant acceleration = 0.2 m/s²                    

Work done by the camper = ?                

actual acceleration acting a'      

m a = m a' - μ mg            

a' = a + μ g                      

a' = 0.2 + 0.05 x 9.8                

a' = 0.69 m/s²                              

Work done = Force x distance

F = m a'                                                            

F = \dfrac{6000}{9.8} \times 0.69

F = 422.44897 N                            

Work done = F x d                          

Work done = 422.44897 x 1000

Work done = 422449 J                  

Work done = 422.45 kJ            

4 0
3 years ago
As a rocket rises, its kinetic energy changes
Bond [772]
<span>Transformed into potential energy</span>
3 0
3 years ago
Read 2 more answers
Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

  k_min  = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

           k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
12
tensa zangetsu [6.8K]

Answer:

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Explanation:

3 0
3 years ago
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