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Vilka [71]
4 years ago
6

I. do these situations involve bernoulli trials? explain.

Mathematics
1 answer:
Masja [62]4 years ago
6 0
<span>B. We can use Bernoulli trials to find how likely is that the majority of a group of 120 people have type A blood, given that 43% of people have type A blood. There are two possible outcomes (a person eithr has Tpe A blood or does not), there is a constant probability of success (43% of people have Type A blood), and the trials are independent (wether each person has Type A blood does not depend wether others have Type A blood).</span>
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Jack got the expression 7x + 1 and then wrote his answer as 1 + 7x. Is his answer an equivalent expression? How do u know? Expla
nadezda [96]
Yes, it is an equivalent expression because even though you move two pieces of an equation it will still equal the same thing, unless there are parentheses involved.
6 0
4 years ago
Read 2 more answers
jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to trave
7nadin3 [17]

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

J(t) = 200 + 80t

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

S(t) = 100t

At what time will Sipho catch up jabu?​

He will catch up in t hours, and t is found when:

S(t) = J(t)

So

100t = 200 + 80t

20t = 200

t = \frac{200}{20} = 10

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

4 0
3 years ago
HURRY PLEASE HELP WILL GIVE BRAINLIEST ANSWER<br> 25 POINTS!!!!
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Answer:

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Step-by-step explanation:

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3 years ago
1-2 sin e cos 20-2 sin 40 = cos (20)
natka813 [3]

Answer:

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Step-by-step explanation:

First I changed the cos^{2}Ф into 1-sin^{2}Ф

I then foiled the (1-2sin^{2}Ф)(1-sin^{2}Ф) and that resulted in 1-sin^{2}Ф-2sin^{2}Ф+2sin^{4}Ф

From there, I then cancelled the two 2sin^{4}Ф and combined like terms and was left with 1-3sin^{2}Ф

Now 1-3sin^{2}Ф ≠ cos(2Ф)

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4 years ago
Which expression below is equal to 5?*
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I believe the answer is the first one
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