The southern states wanted slavery, but the northern did not, so they had a civil war. :P
If you don’t mind can u add the picture it helps me Answer the question better
Yes
Explanation: Information technology, or IT, describes any technology that powers or enables the storage, processing and information flow within an organization. Anything involved with computers, software, networks, intranets, Web sites, servers, databases and telecommunications falls under the IT umbrella.
Answer:
True
Explanation:
A "multimedia presentation" refers to a presentation that uses <em>texts, images, audios, animations, photographs and the like </em>in order to help a particular set of audience understand. The presenter's ideas become clear because the audience can deeply grasp the meaning through different graphics and colors presented.
So, <em>the answer above is definitely true</em> because using animations or transitions figures to control when objects or texts appear can <u>prevent boredom</u> on the end of the audience. This will spark interest on their end.
However, it is important not to overdo it because this will cause further distraction that will divert your audience's attention. It should also be <u>conservative and consistent.</u>
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
