A loop that repeats a specific number of times is known as a(n):

Universal Container wants to understand all of the configuration changes that have been made over the last 6 months. Which tool

rosijanka [135]

Answer:

Set up audit trail

Explanation:

The administrator should set up an audit trail in order to get this information.

An audit trail would give him the record of all the configuration changes that have been made in a file or a database in the last 6 months.

Audit trails can be manual or electronic. It provides history and also documentation support. It can authenticate security and also help to mitigate challenges.

4 0

3 years ago

Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have me

RSB [31]

Answer:

Explanation:

The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.

import java.io.*;

import java.util.*;

class Rainfall

{

Scanner in = new Scanner(System.in);

private int month = 12;

private double total = 0;

private double average;

private double standard_deviation;

private double largest;

private double smallest;

private double months[];

public Rainfall()

{

months = new double[12];

}

public void setMonths()

{

for(int n=1; n <= month; n++)

{

int answer = 0;

while (true) {

System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );

answer = in.nextInt();

if (answer > 0) {

months[n-1] = answer;

break;

}

public void getTotal()

{

total = 0;

for(int i = 0; i < 12; i++)

{

total = total + months[i];

}

System.out.println("The total rainfall for the year is " + total);

}

public void getAverage()

{

average = total/12;

System.out.println("The average monthly rainfall is " + average);

}

public void getLargest()

{

double largest = 0;

int largeind = 0;

for(int i = 0; i < 12; i++)

{

if (months[i] > largest)

{

largest = months[i];

largeind = i;

}

System.out.println("The largest amount of rainfall was " + largest +

" inches in month " + (largeind + 1));

}

public void getSmallest()

{

double smallest = Double.MAX_VALUE;

int smallind = 0;

for(int n = 0; n < month; n++)

{

if (months[n] < smallest)

{

smallest = months[n];

smallind = n;

}

System.out.println("The smallest amount of rainfall was " + smallest +

" inches in month " + (smallind + 1));

}

public static void main(String[] args)

{

Rainfall r = new Rainfall();

r.setMonths();

r.getTotal();

r.getSmallest();

r.getLargest();

r.getAverage();

}

8 0

3 years ago

"Write an iterative function iterPower(base, exp) that calculates the exponential baseexp by simply using successive multiplicat

sp2606 [1]

Answer:

I am writing the function using Python. Let me know if you want the program in some other programming language.

def iterPower(base, exp):

baseexp = 1

while exp > 0:

baseexp = baseexp*base

exp= exp - 1

return baseexp

base = 3

exp = 2

print(iterPower(base, exp))

Explanation:

The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
baseexp is a variable that stores the result and then returns the result of successive multiplication.
while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
Lets see how each iteration works:

1st iteration

baseexp = 1

exp>0 True because exp=2 which is greater than 0

baseexp = baseexp*base

= 1*3 = 3

So baseexp = 3

exp = exp - 1

= 2 - 1 = 1

exp = 1

2nd iteration

baseexp = 3

exp>0 True because exp=1 which is greater than 0

baseexp = baseexp*base

= 3*3 = 9

So baseexp = 9

exp = exp - 1

= 1-1 = 0

exp = 0

Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
return baseexp statement will return the value stored in baseexp which is 9
So the output of the above program is 9.

5 0

3 years ago

A network administrator wants to change the frequency of their wireless network to allow more channels that do not interfere wit

MA_775_DIABLO [31]

Answer:

2.4GHz

Explanation:

In the 2.4 GHz band, 1, 6, and 11 are the only non-overlapping channels

8 0

3 years ago

In this lab, you declare and initialize variables in a C++ program. The program, which is saved in a file named NewAge.cpp, calc

Ne4ueva [31]

Answer:

#include <iostream>

using namespace std;

int main() {

int currentYear = 2020;

int myCurrentAge = 23;

int myNewAge=myCurrentAge+(2050-currentYear);

cout << "My Current Age is " << myCurrentAge << endl;

cout << "I will be " << myNewAge << " in 2050." << endl;

}

Explanation:

Initialize the currentYear with 2020 and myCurrentAge with 23.
Add myCurrentAge with the the result of (2015 - currentYear) and assign this result to myNewAge variable.
Finally display my current age and after that display the new age in 2050.

Output:

My Current Age is 23

I will be 53 in 2050.

6 0

3 years ago