Answer:
def countdown(n):
if n <= 0:
print('Blastoff!')
else:
print(n)
countdown(n-1)
def countup(n):
if n >= 0:
print('Blastoff!')
else:
print(n)
countup(n+1)
number = int(input("Enter a number: "))
if number >= 0:
countdown(number)
elif number < 0:
countup(number)
<u>Outputs:</u>
Enter a number: 3
3
2
1
Blastoff!
Enter a number: -3
-3
-2
-1
Blastoff!
Enter a number: 0
Blastoff!
For the input of zero, the countdown function is called.
Explanation:
Copy the countdown function
Create a function called countup that takes one parameter, n. The function counts up from n to 0. It will print the numbers from n to -1 and when it reaches 0, it will print "Blastoff!".
Ask the user to enter a number
Check if the number is greater than or equal to 0. If it is, call the countdown function. Otherwise, call the countup function.
Answer:
The program in Python is as follows:
word = input("Word: ")
if len(word) < 5:
print("At least 5 characters")
else:
pal = word[0:5]
word = word[0:4]
word = word[::-1]
pal+=word
print(pal)
Explanation:
This gets the word from the user
word = input("Word: ")
This checks if the length of the word is less than 5.
if len(word) < 5:
If yes, this tells the user that at least 5 characters is needed
print("At least 5 characters")
If otherwise
else:
This extracts the first 5 characters of the word into variable named pal
pal = word[0:5]
This extracts the first 5 characters of the word into variable named word
word = word[0:4]
This reverses variable word
word = word[::-1]
This concatenates pal and word
pal+=word
This prints the generated palindrome
print(pal)
Answer:
atof
Explanation:
atof function is used to convert a string to a double.
It takes a single parameter of type const char * and returns a double value.
The function signature is: double atof (const char* str);
In order to use this function in the code, you need to include the header file <stdlib.h>
For example:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str[5] = "0.01";
double d = atof(str);
printf("Value = %f\n", d);
return 0;
}
Answer:
Low CPU utilization and high I/O utilization
Explanation:
