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Keith_Richards [23]
2 years ago
5

How is the pattern matching done in the SQL?

Computers and Technology
2 answers:
fgiga [73]2 years ago
7 0
SQL pattern matching allows you to search for patterns in data if you don't know the exact word or phrase you are seeking.
Alinara [238K]2 years ago
6 0

Answer:

SQL pattern matching allows you to search for patterns in data if you don't know the exact word or phrase you are seeking. This kind of SQL query uses wildcard characters to match a pattern, rather than specifying it exactly. For example, you can use the wildcard "C%" to match any string beginning with a capital C.

Explanation:

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Daniel makes changes to a workbook named “Results.” He saves the file as “New Results” but did not realize that a worksheet name
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What is the output of the following program? #include using namespace std; class TestClass { public: TestClass(int x) { cout &lt
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Answer:

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returntype function_name(){

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Lynna [10]

Answer:

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Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
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