All categories

3 years ago

Help pls I'm rlly bad at math

Mathematics

2 answers:

makkiz [27]3 years ago

8 0

4 is the correct answer ::))

Inessa05 [86]3 years ago

3 0

The answer to the question is 4

You might be interested in

A number x divided by 7 is less than −3.

agasfer [191]

Answer:

x<-21

Step-by-step explanation:

x/7<-3

x<-21

7 0

4 years ago

Read 2 more answers

What is the measure of angle ABC

zvonat [6]

ANSWER = c. 63°

EXP:

>ABC = 1/2(x + y)

3 0

3 years ago

Student tickets cost $6.25 each at a local movie theater. Which proportion could be used to find the number of student tickets,

leva [86]

Answer:a

Step-by-step explanation:all the other ones are not smart

if u think about it

U can’t dived t and I so just do the one that doesn’t do that

8 0

3 years ago

4. ASAP I NEED HELP

vodomira [7]

Answer:

The value of x = 5 and y = 2.

Step-by-step explanation:

Here, given DECK is a parallelogram.

Also, KT = 2x + y , DT = x + 2y , TE = 12 and TC = 9

Now, in parallelogram:

DIAGONALS IN A PARALLELOGRAM BISECT EACH OTHER

Also, in the parallelogram DECK,

Sides DC and KE are two diagonals.

⇒ T is the mid point of AC and KE.

⇒ KT = TE and DT = TC ( as diagonals are bisected)

⇒ 2 x + y = 12 and x + 2y = 9

So here, the set of two equations are:

2 x + y = 12 ....... (1)

x + 2 y = 9 ....... (2)

Multiply (2) with -2 and add with (1), we get:

2 x + y - 2 x - 4 y = 12 - 18

or, - 3 y = - 6

or, y = 2

If y = 2, then x + 2 (2) = 9 or, x = 5

Hence the values of x = 5, y = 2

7 0

4 years ago

Find two positive numbers satisfying the given requirements. The product is 216 and the sum is a minimum. (No Response) (smaller

fgiga [73]

Answer:

$x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

Step-by-step explanation:

Let the first number is x1 and other number is y1 then

$x1 * y1 =216$

Therefore

$y1=$ $\frac{216}{x1}$

also there sum is

$s1 =x1+y1$ ....Eq(1)

Putting the value of y1 in the previous equation

$s1\ =x1 + \frac{216}{x1}$ ........Eq(2)

Differentiate the the Eq(2) with respect to x1 we get

$\frac{ds1}{dx1} \ =\ 1+216*\frac{1}{-x1^{2} }$

$\frac{ds1}{dx1} \ =\ 1-\frac{216}{x1^{2} }\ =\ 0$

${x1^{2} }\ =\ 216\\ x1=\sqrt{216}$

Putting the value of X1 in Eq(1) we get

$y1=\frac{216}{\sqrt{216} } \\y1=\frac{216*\sqrt{216} }{216} \\y1=\ \sqrt{216}$

So $x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

6 0

4 years ago