Answer:
Option C. is the correct answer
Step-by-step explanation:
Choose any value of x and find the values of y. Then plot a graph using all that points. These will neither parallel nor perpendicular.
<span>The
value of the determinant of a 2x2 matrix is the product of the top-left
and bottom-right terms minus the product of the top-right and
bottom-left terms.
The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.
= [ (1)(-3)] - [ (7)(0) ]
= -3 - 0
= -3
Therefore, the determinant is -3.
Hope this helps!</span>
<span>
Question 2.2. Which ordered pairs make the inequality true?</span><span>2x + y > –4</span>The solutions are (-1, 2) and (1, -5), look at the graph in the attachment.
Question 3.3. What is the slope of the line represented by the equation?There is no equation
Question 4.4. What is the slope of the line represented by the equation 6x - 3y = 4?Convert to slope-intercept form:
6x - 3y = 4
Subtract 6x to both sides:
-3y = -6x + 4
Divide -3 to both sides:
y = -6/-3x + 4/-3
Simplify:
y = 2x - 4/3
Now it's in slope intercept form, y = mx + b, where 'm' is the slope. So the slope here is 2.
Question 5.5. What is the simplified form of the expression?15y - 3(4y + 10)
Distribute -3 into the parenthesis:
15y - 12y - 30
Combine like terms:
3y - 30
Hello, Oliveria. I am saddened to hear that you have started a whole rewrite of your plan for mathematics, but fear not; there are a couple of resources and websites that are always ready for you. For starters, visit websites that have at least 7th or 6th grade and up in benchmark mathematics content; this would be IXL, KhanAcademy, or even take some of the lesson tutorials from places like Symbolab and mathpoppa (<span>please, don't use the algebra calculator a lot. It will add more to your demise). Any how, you can always ask your guidance counselor at your school for help, or even your algebra teacher for some tutorials on certain topics. Always at least try to ask for help from your teacher or friends; even if you think they can't help much, it is always best to try
It seems that you have enough self direction and initiative to go on this route, now you just need the additional boosts :)</span><span />