where, E^{o} (Ag+/Ag) = std. reduction potential of Ag+ = 0.7994 v
and Sn2+/Sn = std. reduction potential of Sn2+ = -0.14 v
Thus, E^{o}cell = 0.7994v - (-0.14v) = 0.9394 v
Now, ΔG^{o} = -nF
,
where, n = number of electrons = 2
F = Faraday's constant = 96500 C
∴ΔG^{o} = 2 X 96500 X 0.9394 = -1.18 X
Now, using Nernst's Equation we have,
![[tex]E_{cell} = 0.9394 - \frac{2.303X298}{2X96500}log \frac{0.0115}{ 3.5^{2} }](https://tex.z-dn.net/?f=%20%5Btex%5DE_%7Bcell%7D%20%3D%200.9394%20-%20%5Cfrac%7B2.303X298%7D%7B2X96500%7Dlog%20%5Cfrac%7B0.0115%7D%7B%203.5%5E%7B2%7D%20%7D%20)
E_{cell} = 0.9765 v
Finally, ΔG = -nFE = -2 X 96500 X 0.9765 = -1.88 X
Answer:
The charge on iodine is 2-
Molarity is the ratio of the moles and the volume. The mass of 2.6 M sodium phosphate solution is 2131.22 gms.
<h3>What is mass?</h3>
Mass is the product of the moles and the molar mass of the substance. It is given as,
Mass = Moles × Molar mass
The moles from molar concentration is used to calculate mass as:
Mass = Molarity × volume × molar mass
= 2.6 × 5.0 × 163.94
= 2131.22 gms
Therefore, 2131.22 gms is the mass of sodium phosphate.
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The molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.
<h3>How to calculate molar mass?</h3>
The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.
However, the number of moles of the gas in this question needs to be calculated first using the ideal gas law equation:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- T = temperature
- R = gas law constant
1.04 × 0.854 = n × 0.0821 × 302
0.888 = 24.79n
n = 0.888/24.79
n = 0.036mol
Molar mass of gas = 3.82g/0.036mol
Molar mass = 106.66g/mol
Therefore, the molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.
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