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Andrews [41]
3 years ago
11

What is the charge on iodine (I) when it forms an ion? (1 point)

Chemistry
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

The charge on iodine is 2-

ASHA 777 [7]3 years ago
6 0

Answer:

1-

Explanation:

Iodine is a group 7 elements. Group 7 elements are called halogens.

Iodine as a group 7 element has 7 electrons in its outermost shell and needs just one more to complete its octet state. Iodine is therefore electronegative with a charge of -1

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If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?
Pie

<u><em>Answer:</em></u>

m = \frac{E}{c^2}

c = \sqrt{\frac{E}{m} }

E = 12.8 J

<u><em>Explanation:</em></u>

<u>Part 1: Solving for m</u>

<u>We are given that:</u>

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

m = \frac{E}{c^2}

<u>Part 2: Solving for c</u>

<u>We are given that:</u>

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

c^2 = \frac{E}{m}\\  \\ c=\sqrt{\frac{E}{m}}

<u>Part 3: Solving for E</u>

<u>We are given that:</u>

m = 80 and c = 0.4

<u>To get the value of E, we will simply substitute in the given equation: </u>

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0
4 years ago
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8 0
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Please anser this asap
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