All categories

2 years ago

How many grams of sodium Phosphate is needed to prepare 5.0 L of a 2.6M solution ?

1 answer:

6 0

Molarity is the ratio of the moles and the volume. The mass of 2.6 M sodium phosphate solution is 2131.22 gms.

Mass is the product of the moles and the molar mass of the substance. It is given as,

Mass = Moles × Molar mass

The moles from molar concentration is used to calculate mass as:

Mass = Molarity × volume × molar mass

= 2.6 × 5.0 × 163.94

= 2131.22 gms

Therefore, 2131.22 gms is the mass of sodium phosphate.

Learn more about mass here:

brainly.com/question/9829994

#SPJ1

You might be interested in

Students conducted an investigation into the three elements listed above. What type of element should Sulfur be labeled?

soldier1979 [14.2K]

MetAllllllllllllllll

7 0

3 years ago

Read 2 more answers

What is the SI base unit for length?

sp2606 [1]

The SI base unit for length is meter.

In order to make smaller measurements, you can use the centi-, milli-, micro-, etc. prefixes.

When you want to reference larger measurements, you can use the kilo-, mega-, giga- and prefixes such as those.

5 0

3 years ago

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

7 0

3 years ago

if a leaf falls from a tree we assume that it is in free fall and not affected by air resistance, how many force vectors does th

lakkis [162]

Just the force of gravity down.

7 0

3 years ago

Calcium hydroxide + hydrochloric acid → calcium chloride + water

Lubov Fominskaja [6]

Answer:

Explanation: iIt is a neutralization reaction and neutralization reaction is a reaction between and acid and base to give salt and water. In the question above, Ca(OH)2 is the base and HCl is the acid, Ca(Cl)2 is the salt and H2O.

5 0

3 years ago

Read 2 more answers