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kotegsom [21]
2 years ago
5

1. What is the best method for removing water from a hydrated compound?

Chemistry
1 answer:
Helga [31]2 years ago
6 0
The traditional method is to heat the compound in an oven, on a hot plate or over a Bunsen burner. Waters of hydration are loosely bound in the compound and can be driven off at temperatures below the melting point of the compound. So the answer is heating.
You might be interested in
How many grams are there in 9.03 x 1023 molecules of CO2?
wariber [46]

Answer:

The correct answer is - 66g.

Explanation:

Given:

molecules of CO2 = 9.03 x 10^23

We know:

1 mole of any substance = 6.02x10^23 molecules. (Avogadro's number)

M (CO2) = 12 + (2x16) = 12 + 32 = 44g

Solution:

The mass of CO2 with 9.03x10^23 molecules would be:

44g of CO2 = 6.02x10^23 molecules.

So, the mass in grams of CO2 (X) = 9.03x10^23 molecules

Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g

Thus, the correct answer would be - 66gm.

5 0
2 years ago
A solution of CuSO4 is labelled 0.01 M. How much CuSO4 in grams, must be used to make 1 liter of solution?
Gala2k [10]

answer: C) 1.6 g

explanation: Molarity is the moles of solute present per liter solution.

The given molarity of the solution is 0.01 M.

I hope I can help you :)

if it’s correct please mark me brainliest

6 0
3 years ago
Suppose 2.4 g of Mg reacts with 10.0 g of O2, to create magnesium oxide. How much magnesium oxide is produced?
o-na [289]

Answer:

3.98 g

Explanation:

Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

2~Mg(s) + O_2 (g)\rightarrow 2~MgO (s)

\\

Step 2. Calculate the number of moles of magnesium:

n_{Mg} = \frac{2.4~g}{24.305~g/mol} = 0.0987~mol

\\

Step 3. Calculate the number of moles of oxygen:

n_{O_2} = \frac{10.0~g}{32.00~g/mol} = 0.3125~mol

\\

Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

eq_{Mg} = \frac{0.0987~mol}{1} = 0.0987~mol

Equivalent of oxygen:

eq_{O_2} = \frac{0.3125~mol}{2} = 0.15625~mol

Therefore, Mg is the limiting reactant.

\\

Step 5. According to the stoichiometry of this reaction:

n_{Mg} = n_{MgO} = 0.0987~mol

\\

Step 6. Convert the number of moles of MgO into mass:

m_{MgO} = 0.0987~mol\cdot 40.304~g/mol = 3.98~g

5 0
3 years ago
Can we used glass beaker instead of plastic cup for the calorimeter experiments?
Mice21 [21]
No, because plastic cups can be dissolved by organic compounds. Moreover, they are easily melted so a highly exothermic reaction can not be studied using them. 
4 0
3 years ago
Help for this practice work
allochka39001 [22]

Answer:

It's the third option.

Explanation:

In order for the chemical equation to be correctly it needs the same number of atoms of each element on both sides of the equal sign

8 0
2 years ago
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