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kotegsom [21]
3 years ago
5

1. What is the best method for removing water from a hydrated compound?

Chemistry
1 answer:
Helga [31]3 years ago
6 0
The traditional method is to heat the compound in an oven, on a hot plate or over a Bunsen burner. Waters of hydration are loosely bound in the compound and can be driven off at temperatures below the melting point of the compound. So the answer is heating.
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Use the activity series below to predict the products of each of the following reactions. Do not worry about
myrzilka [38]

Answer:

i) CCl₄ and Br₂ does not react

ii) CBr₄ + Cl₂ → CCl₄ + Br₂

Explanation:

i) CCl₄ + Br₂ (no reaction)

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction

ii) CBr₄ + Cl₂

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;

CBr₄ + Cl₂ → CCl₄ + Br₂

The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.

8 0
2 years ago
What volume (in mL) of a 0.113 M NaCl solution contains 0.087 mol NaCl?
Helen [10]
Hello I a m s o m o n e I n t h e w o r l d
5 0
3 years ago
If an object has an acceleration of 9.8 m/s and a force of 58.8N what is the mass of an object ? What could the object be
Makovka662 [10]

Answer:

The mass of an object  is 0.6122 Kg

Explanation:

Given:

Acceleration  = 9.8 m/s

Force  = 58.8 N

To Find:

Mass of an object = ?

Solution:

We know that according to newtons 2nd law

Force is the product of the mass and acceleration

F= ma

where

F = Force

m = mass

a =  Acceleration

Substituting the values,

58.8 = m X  9.8

m= \frac{58.8}{9.8}

m = 0.6122 kg

7 0
3 years ago
Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to
Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

P_{2} =\frac{T_{2} P_{1} }{T_{1} }

P_{2}=\frac{(337K)(0.55atm)}{418K}

P₂=0.44 atm

8 0
3 years ago
Our recorded observations are called.
trapecia [35]

Answer:  Raw data, perhaps.

Explanation:  I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice.  It reflects the data was recorded, but not yet processed to provide a conclusion or observation.

If one were a bit snarky, other possiblities include

  • a pile of dung
  • my labmate's scrawls, or
  • the best web results I could find

5 0
2 years ago
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