Answer:
1.3 s
Explanation:
A first-order reaction can be represented through the following expression.
ln [A] = ln [A]₀ - k.t
where,
[A] is the concentration of the reactant A at a certain time t
k is the rate constant
When the concentration decreases to half its value ([A] = 0.5 [A]₀), the time elapsed is known as half-life t(1/2).
ln (0.5 [A]₀) = ln [A]₀ - k.t(1/2)
ln 0.5 = -k.t(1/2)
t(1/2) = -ln 0.5 / k = - ln 0.5 / (0.54 s⁻¹) = 1.3 s
The type of bond between the atoms in the carbon dioxide molecule is COVALENT BOND.
Covalent bond involves sharing of electrons between the atoms that are involved in the chemical reaction. The one carbon atom and the two oxygen atom that formed the carbon dioxide molecule share electrons in such a way that the outermost shell of each atom is made up of eight electrons.<span />
Answer:
The answer is KINETIC energy
Explanation:
The baseball is moving and Kinetic energy correlates to movement.
Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury