Answer: The answer is 
Step-by-step explanation: Given that in a small auditorium, 320 peoples can sit. The number of peoples who can sit in the auditorium is represented by 'p'.
Since no more that 320 people can sit in the auditorium, so the number of persons who can sit there lies between 0 and 360.
Therefore, the inequalities are

Combining both of the above inequalities, we get

Thus, the required inequality is
.
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
combined velocity of the system = 0.033 m/s.
Step-by-step explanation:
taking the bullet and block as single system since there is no external force involved momentum is conserved .
initial momentum of the bullet = mv
where m is the mass of bullet and v is velocity of bullet.
and initial momentum of block = 0 since its velocity is 0.
therefore initial momentum of the system = mv
= 0.005×40
= 0.2
when the bullet stick of together with the block let the combined velocity of the system be V
therefore applying conservation of momentum
mv = (M+m)V
0.2=(6+0.005)V
therefore V = 0.033 m/s