Answer:
The acceleration is 
and the distance covered is 97.17 m.
Explanation:
Given that,
Initial speed of an automobile, u = 60 km/hr = 16.67 m/s
Final speed of an automobile, v = 80 km/hr = 22.2 m/s
Time, t = 5 s
We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :
Let d is the distance covered. Using the third equation of motion to find it as follows :
So, the acceleration is and the distance covered is 97.17 m.
Answer:
The coefficient of static friction is : 0.36397
Explanation:
When we have a box on a ramp of angle 
, and the box is not sliding because of friction, one analyses the acting forces in a coordinate system system with an axis parallel to the incline.
In such system, the force of gravity acting down the incline is the product of the box's weight times the sine of the angle:
Recall as well that component of the box's weight that contributes to the Normal N (component perpendicular to the ramp) is given by:
and the force of static friction (f) is given as the static coefficient of friction (
) times the normal N:
When the box starts to move, we have that the force of static friction equals this component of the gravity force along the ramp:
Now we use this last equation to solve for the coefficient of static friction, recalling that the angle at which the box starts moving is 20 degrees:
Answer:
the force constant k = 2.369 N/m
Explanation:
Given that:
A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.
with period T = 0.500 s and a mass of 0.0150 kg, Then the force constant can be calculated by using the formula:
where;
T = time period
m = mass
k = force constant.
By making k the subject of the formula; we have:
replacing our given values , we have:
k = 2.369 N/m
Answer:
22 m/s
Explanation:
PEf +KEf =PE0 +KE0 →PE0 −PEf =KEf
−mgΔy= 1 mv2 →v= −2gΔy = −2(9.8 m/s2)(−25 m)=22 m/s
