Answer:
1.97 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s²
Solving the above equation we get
So, the time the package was in the air is 1.97 seconds
The message refers to the ideas, thoughts, and feelings being communicated (C).
<span>A message can be defined as a short written, verbal or recorded communication containing information that is sent to a person. The person sends or receives the message cannot be contacted directly. A message can also be a moral, political, social point that is meant to be passed onto society via a speech, movie, art exhibition, music and many more. It can also be a formal communique sent by a representative of one government to another government.</span>
Answer:
As the object falls it loses potential energy and gains kinetic energy
Explanation:
When the object reaches the ground its final KE will be equal to its original PE
Find the amount of labor necessary to move an object along the specified orientated curve given the force field F. y = 3x2 on the parabola from (0, 0) to F = (y, x) (4, 48).
<h3>How can you determine the work a force field performs along a curve?</h3>
A variable force's infinitesimal work can be defined in terms of the force's components and the displacement along the path,
<h3>How do you assess the force field F's work?</h3>
(c) Next, determine the work that the force field F performed on the object to move it through the field by moving it along the vector d. W = F d is the formula for work.
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Answer:
22.7 meters
Explanation:
Let's remind the difference between distance and displacement:
- distance: the total distance travelled by an object in all its paths
- displacement: the different between the final and initial position of the object
In this case, the problem asks to find the distance covered by the ball. This will be the sum of the distances covered by the ball in each part of its motion, therefore:
(instead, the displacement will be the difference between the final and initial position of the ball, therefore:
)
