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jolli1 [7]
3 years ago
6

in the derivation of the time period of a pendulum in electric field when considering the fbd of bob to find the g effective why

do we neglect tension
Physics
1 answer:
Neko [114]3 years ago
8 0

Answer:

we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.

The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.

that's what I know so far

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Explanation:

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3 years ago
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What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?
Alchen [17]

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

  • When a simple pendulum swings back and forth, it has some energy associated with its motion.
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  • The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
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8 0
4 years ago
If a = 2.0 cm, b = 5.0 cm, and i = 20 a, what is the magnitude of the magnetic field at the point p?
attashe74 [19]

If a = 2.0 cm, b = 5.0 cm, and i = 20 a,  6.0 μt is the magnitude of the magnetic field at the point p, So the correct option is (a).

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

B_{1} = μ_{0} i \frac{\pi }{6} / 4\pi (a+b)

B_{2} = μ_{0} i \frac{\pi }{6} / 4\pi b

As, B_{1} is moving down and B_{2} is moving up so,

B_{2} - B_{1} = (μ_{0} i \frac{\pi }{6} / 4\pi b) -  [μ_{0} i \frac{\pi }{6} / 4\pi (a+b)]

B_{2} - B_{1} = μ_{0} i 24 / (\frac{1}{b} - \frac{1}{a+b} )

B_{2} - B_{1} = \frac{4\pi *10^{-7}*20 }{24} (\frac{1}{0.05} -\frac{1}{0.02})

B_{2} - B_{1} = 5.98×10^{-6} T ≈ 6μT

Therefore,  6.0 μt is the magnitude of the magnetic field .

Learn more about  magnetic field here;

brainly.com/question/23096032

#SPJ4

3 0
2 years ago
The KE of a body becomes 2 times of its original value then the new momentum will be more than its initial momentum by​
sladkih [1.3K]

Answer:

√2

Explanation:

If the final kinetic energy is 2 times the initial kinetic energy:

KE = 2 KE₀

½ mv² = 2 (½ mv₀²)

v² = 2 v₀²

v = √2 v₀

Therefore, the ratio of the final momentum to the initial momentum is:

p / p₀

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In a parallel circuit the component with the highest resistance will have a low electric current.
statuscvo [17]
Should be true.

it's been awhile since I was learning this
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3 years ago
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