Your pendulum does a complete swing in 1.9 seconds. You want to SLOW IT DOWN so it takes 2.0 seconds.
Longer pendulums swing slower.
You need to <em>make your pendulum slightly longer</em>.
If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom. You can add weight or cut some off, and it won't change the speed a bit.
Answer:
Net force = 25N and in the right direction
Explanation:
mass of box, m = 50kg
Force of block = 150N
Friction force = 125N
150 - 125 = 25N
the force applied to the block is greater than the friction force. there the force applied will overcome the friction force and move in the right direction of the force applied
IF the bag is suspended freely in mid-air and free to move
without friction, then the linear momentum is the same both
before and after the hit.
Momentum of the bullet before the hit = ( m₁ v₁ ).
Momentum of the (bullet + bag) after the hit = (m₁ + m₂) (v₂) .
Momentum is conserved, so we can say that ...
( m₁ v₁ ) = (m₁ + m₂) (v₂)
v₂ = ( m₁ v₁ ) / (m₁ + m₂)
Usually the mass of the bag is much much more than the mass
of the bullet, so the mass of the bullet can be ignored after the
hit, and the formula is very closely ...
v₂ = v₁ ( m₁ / m₂ ) .
Stop apologizing for your English. It's better than many native
Americans writing on this site. Be proud.
Answer:
Explanation:
mass of each object = m
momentum conservation: mv₁ + mv₂ = 2mv, so v = (v₁ + v₂)/2
Initial KE = mv₁²/2 + mv₂²/2 = m(v₁² + v₂²)/2
final KE = (2m)v²/2 = m(v₁ + v₂)²/4
Change in KE = m(v₁² + v₂²)/2 - m(v₁ + v₂)²/4 = m(v₁ + v₂)²/4
= m(v₁² + v₂² + 2v₁v₂)/4 = (1/2) m(v₁² + v₂²)/2 + mv₁v₂/2
Fraction loss = change in KE / initial KE = 1/2 + v₁v₂/(v₁² + v₂²)
Answer:
Spring constant in N / m = 6,000
Explanation:
Given:
Length of spring stretches = 5 cm = 0.05 m
Force = 300 N
Find:
Spring constant in N / m
Computation:
Spring constant in N / m = Force/Distance
Spring constant in N / m = 300 / 0.05
Spring constant in N / m = 6,000
