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Step2247 [10]
3 years ago
9

Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv

er pass through
Physics
1 answer:
shusha [124]3 years ago
8 0

Answer:

Two.

Explanation:

  • A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.
  • One complete wave consists of two loops.
  • It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.
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In a paragraph of no less than five complete sentences, explain how the bubble gum experiment demonstrates the Law of Conservati
Marianna [84]

Answer:

The bubble gum experiment demonstrates the law of conservation of mass in that even though the bubble gum has lost mass, this loss in mass is not because some matter present in the gum has been destroyed, but it has changed  form and has been removed from the gum.

Explanation:

In this science experiment, students investigate whether or not chewing gum should be considered eating. During the process of chewing the gum, the gum loses mass. The experiment is used to demonstrate the law of conservation of mass which states that matter can neither be created nor destroyed but may change from one form to another.

The loss in mass of the gum is due to the fact that the sugar present in the gum has changed form and has been removed from the gum. During the process of chewing the gum, the sugar in solid form present in the gum is dissolved in the saliva found in the mouth. The dissolved sugar is then swallowed and passes into the digestive tract for digestion. This shows that even though the bubble gum has lost mass, this loss in mass is not because some matter present in the gum has been destroyed, but it has changed  form and has been removed from the gum, This demonstrates the law of conservation of mass.

4 0
3 years ago
A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)
loris [4]
Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s
7 0
3 years ago
The rotational inertia of your leg is greater when your leg is
ryzh [129]

It would be bent, and your welcome

4 0
3 years ago
Read 2 more answers
A 25 N force at 60° is required to set a crate into motion on a floor. What is the value of the static friction?
True [87]
The normal force of the force given is calculated through the equation,
 
                                 Fn = F(sin θ)
where Fn is the normal force, F is the force, and θ is the angle. 
  
                                Fn = (25 N)(sin 60°) = 21.65 N

The x-component of the force applied is,
                               Fx = (25 N)(cos 60°) = 12.5 N

The value of the coefficient of static friction is calculated through the equation,
                              F = μFn
                              μ = Fx / Fn = 12.5 N / 21.65 N = 0.577
3 0
3 years ago
Five equal negative charges are uniformly spaced in a semicircular
balu736 [363]

Answer:

The direction is that of a 3rd quadrant angle

Explanation:

when you have 2 45 angles it equals to 90 then with the 90 we multiply by 2 due to the 2 adjacent angles equating to 180 which swings it to the 3rd quadrant angle

6 0
4 years ago
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