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Svetach [21]
3 years ago
8

Which cross section does any type of prism have

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer: The answer is a Triangle

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1,958.55 divided by 15?????
fiasKO [112]
answer is 130.57
uwu
7 0
3 years ago
Write 7.530 in word form.
Romashka [77]

Answer:

seven point five three zero

hope this helps you

3 0
3 years ago
For the rhombus below, find the measure of angles 1,2,3 and 4.
Alexus [3.1K]

Answer:

∠1 is 33°

∠2 is 57°

∠3 is 57°

∠4 is 33°

Step-by-step explanation:

First off, we already know that ∠2 is 57° because of alternate interior angles.

Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.

Then, you basically just do some other pain-in-the-butt things after.

Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.

Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.

57° + 90° = 147°

180° - 147° = 33°

∠1 is 33°

Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.

5 0
3 years ago
CAN SOMEONE HELP ME PLEASE ILL GIVE BRAINLEST..I need step to step equation thanks​
Dmitrij [34]

Answer:

The required co-ordinate is (-2, -5).

Step-by-step explanation:

For a given point, reflection of a point (x, y) across a horizontal line y = k, the reflected co-ordinates will be: $ R_{y = k} = (x, 2k - y) $.

Here, (x, y) = (-2, 7) then reflection along the line y = 1, we get:

$ R_{y = 1} (-2, 7) = (-2, 2(1) - 7) $

= (-2, -5)

The reflected point is (-2, -5).

5 0
4 years ago
Question 4. Write an equation of the line that passes through (1, 2) and (3,-2).
VashaNatasha [74]

Answer:

y=-2x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-2)/(3-1)

m=-4/(2)

m=-4/2

m=-2

y-y1=m(x-x1)

y-2=-2(x-1)

y-2=-2x+2

y=-2x+2+2

y=-2x+4

Please mark me as Brainliest if you're satisfied with the answer.

5 0
3 years ago
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