Answer:
3× + 16 = 22.75
3× = 22.75 - 16
<u>3x</u><u> </u>= <u>6</u><u>.</u><u>75</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>3 3
x = 2.25
Triangles congruent by ASA have two pairs of congruent sides and an included congruent angle.
The graph indicates that sides TV, HG, and AB are congruent, and that sides TU, FG, and BC are congruent. It also indicates that angles U, F, and C are congruent, and that angles G and B are congruent. Notice that angle U of triangle TUV is not an included angle; this eliminates triangle TUV as it can't be congruent to another triangle by ASA with the information provided.
That leaves triangles FGH and ABC. Evidently, angles G and B are included angles, so these triangles are congruent by ASA.
Answer:
b. ΔHGF and ΔABC
Answer:
y = -x + 7
General Formulas and Concepts:
<u>Pre-Algebra</u>
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
- m - slope
- b - y-intercept
Step-by-step explanation:
<u>Step 1: Define</u>
[Standard Form] 5x + 5y = 35
<u>Step 2: Rewrite</u>
<em>Find slope-intercept form.</em>
- Subtract 5x on both sides: 5y = -5x + 35
- Divide 5 on both sides: y = -x + 7
Answer:
y²=4√2.x
Step-by-step explanation:
The focus is at (0,4) and directrix is y=x or x-y =0, for a parabola P.
The distance between the focus and the directrix of the parabola P is
=
{Since the perpendicular distance of a point (x1, y1) from the straight line ax+by+c =0 is given by 
}
Let us assume that the equation of the parabola which is congruent with parabola P is y²=4ax
{Since the parabola has vertical directrix}
Hence, the distance between focus and the directrix is 2a = , {Two parabolas are congruent when the distances between their focus and the directrix are same}
⇒ a=√2
Therefore, the equation of the parabola is y²=4√2.x (Answer)
