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jonny [76]
3 years ago
5

Jessica went shopping and bought a pair of jeans that were on sale for 25% off the original price of $23.98. A 6% tax was also a

dded on to the sale price. Enter the total amount that Jessica spent on the jeans. Round your answer to the nearest cent, if necessary.
Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

$19.07

Step-by-step explanation:

First off we need to find the discounted price of the jeans that Jessica bought.

We find the discount by multiplying the original price by 25% or 0.25

Discount Price = 23.98 x 0.25

Discount Price = 5.99

Now we subtract the discount from the original price.

Discounted Price = 23.98 -5.99

Discounted Price = 17.99

Now that we have the discounted price, we then compute for the sales tax.

Sales Tax = 17.99 x 0.06

Sales Tax = 1.08

Then we add the sales tax to the discounted price.

Total Price = 17.99 + 1.08

Total Price = $19.07

Jessica spent $19.07 on the jeans.

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Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

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