3 years ago

The point

1 answer:

4 0

I don’t know the answer to this but I am working on it right now

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Aleksandr-060686 [28]

Answer:

0.0821

Step-by-step explanation:

If the arrival rate is 50 customers per hour (60 minutes), then the expected number of customers in 3 minutes is:

$\lambda=\frac{50}{60}*3\\ \lambda=2.5\ customers/3\ minutes$

Assuming a Poisson distribution with 2.5 customers per 3 minutes, the probability that zero customers arrive for 3 minutes is:

$P(x=k)=\frac{\lambda^k*e^{-\lambda}}{k!}\\P(x=0)=\frac{2.5^0*e^{-2.5}}{0!}\\ P(x=0)=0.0821$

The probability that the bank stays empty for three minutes is 0.0821.

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3 years ago