Answer:
If a force of 40newton is applied to the end of a wire 4m long and produces an extension of 0.24mm. If the diameter of the wire is 2mm, calculate the strain energy
Explanation:
stress=force/area (n/m^2)
strain=deformation/length (m/m)
The time to distance ratio is 2.1:1 , making the first time 5 seconds, the first distance 18.9 m, and the second time 15 seconds. I hope this helps!
Answer:
No, they are not because when you stretch the rubber band you are deforming it but with the spring it is made to go up and down.
Explanation:
Answer:
When object falls freely we can say
its initial speed will be ZERO
and its acceleration due to gravity must be
a = g = 9.8 m/s^2a=g=9.8m/s2
Now we need to find the distance of free fall in 3 s of time
So here we will use kinematics
y = v* t + \frac{1}{2} at^2y=v∗t+21at2
now we will plug in all values in it
y = 0 + \frac{1}{2}* 9.8 * 3^2y=0+21∗9.8∗32
y = 44.1 my=44.1m
So it will fall by total distance of 44.1 m