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zzz [600]
3 years ago
12

What two quantities are crucial to quantifying the translational kinetic energy of an object?

Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

Moment of inertia and angular velocity.

Explanation:

The translational kinetic energy of an object is possessed when the object is showing rotational motion. It can be given by the formula as :

KE=\dfrac{1}{2}I\omega^2

Here,

I is the moment of inertia of the object

\omega is the angular velocity of the object

So, the translational kinetic energy of an object is given by moment of inertia and angular velocity of the object. Hence, this is the required solution.

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A motorist drives along a straight road at a constant speed of 15 m/s. just as she passes aparked motorcycle police officer , th
allsm [11]

Explanation:

Distance traveled by motorist =(15.0m/s)t

Distance traveled by policeman =1/2(2.00m/s2)t2

(a) Intercept occurs when 15.0t =t2or t=15.0s.

(b) x(officer)=1/2(2.00m/s2)t2= 225m

4 0
1 year ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th
Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion  (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x  (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0
3 years ago
A 9.0 volt battery is connected to four resistors in a parallel circuit. The resistors have 7.0 Ω, 5.0 Ω, 4.0 Ω, and 2.0 Ω respe
lidiya [134]
Series,effective resistance =R₁+R₂+R₃...
parallel,effective resistance 1/R=1/R₁ +1/R₂ +1/R₃...
 
Here,effective resistance 1/R =1/7 +1/5+ 1/4+1/2  
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                                       R = 1/1.092 =0.915Ω
voltage V=9 V 
current I=V/R
           
I=9 / 0.915
            =9.83 A
5 0
3 years ago
Read 2 more answers
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Answer:

Kepler's first law means that planets move around the Sun in elliptical orbits. An ellipse is a shape that resembles a flattened circle. ... It is zero for a perfect circle.

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Based on the data, which prediction should he expect to occur? A2 repels B1. C2 attracts B2. B1 repels C1. A1 attracts C2.
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I believe the answer is a1
6 0
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