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zzz [600]
3 years ago
12

What two quantities are crucial to quantifying the translational kinetic energy of an object?

Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

Moment of inertia and angular velocity.

Explanation:

The translational kinetic energy of an object is possessed when the object is showing rotational motion. It can be given by the formula as :

KE=\dfrac{1}{2}I\omega^2

Here,

I is the moment of inertia of the object

\omega is the angular velocity of the object

So, the translational kinetic energy of an object is given by moment of inertia and angular velocity of the object. Hence, this is the required solution.

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For a plane mirror,how is the object s related to the distance s?
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5 0
3 years ago
A 1,103 kg car traveling at 18 m/s to the south collides with a 4,919 kg truck that is initially at rest at a stoplight. The car
Zigmanuir [339]

ANSWER

3.30\text{ m/s}

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

Initial velocity of car, uc = 18 m/s

Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

This implies that:

m_cu_c+m_tu_t=m_cv_c+m_tv_t

Since the car and the truck stick together after the collision, they will have the same final velocity.

Hence:

m_cu_c+m_tu_t=(m_c+m_t)v_{}_{}

Substitute the given values and solve for v (final velocity):

\begin{gathered} (1103\cdot18)+(4919\cdot0)=(1103+4919)v \\ \Rightarrow19854=6022v \\ \Rightarrow v=\frac{19854}{6022} \\ v=3.30\text{ m/s} \end{gathered}

That is the final velocity of the two-vehicle mass.

8 0
1 year ago
A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is
ser-zykov [4K]

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

5 0
3 years ago
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