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Dima020 [189]
3 years ago
15

Please help will make brainlist.

Physics
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

the box should be 1 N

Explanation:

forces are equal left and right, and up and down. hope that helped, sorry if its wrong...

Greeley [361]3 years ago
4 0
The answer is 1N. It also gets friction from the sand.
You might be interested in
A spring with spring constant of 26 N/m is stretched 0.22 m from its equilibrium position. How much work must be done to stretch
Evgen [1.6K]

Answer:

1.503 J

Explanation:

Work done in stretching a spring = 1/2ke²

W = 1/2ke²........................... Equation 1

Where W = work done, k = spring constant, e = extension.

Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.

Substitute into equation 1

W = 1/2(26)(0.34²)

W = 13(0.1156)

W = 1.503 J.

Hence the work done to stretch it an additional 0.12 m = 1.503 J

8 0
3 years ago
When you look at yourself in a convex mirror, you appear to be ¼ your actual size. If you are standing 1.0 m in front of the mir
Nookie1986 [14]

Answer:

The focal length is   f  =  -0.2 \  m

The radius of curvature is R = -0.4 \  m

Explanation:

From the question we are told that

       The magnification of the mirror is  m =  \frac{1}{2}

       The distance of the person from the mirror(the object distance ) is  u = - 1.0 \ m

        The negative sign shows that it is been placed in front of the mirror

         

Generally the magnification of the mirror is mathematically represented as

       m  =  \frac{v}{u}

=>   \frac{1}{4}  = \frac{v}{-u}

=>   v  =  \frac{- 1}{4}

Generally from the lens equation we have that

        \frac{1}{f}  = \frac{1}{u}  + \frac{1}{v}

=>     \frac{1}{f}  = \frac{1}{-1 }  + \frac{1}{-\frac{1}{4} }

=>     f  =  -0.2 \  m

Generally the radius of curvature is  mathematically represented as

         R = 2 *  f

=>      R = 2 *   - 0.2

=>      R = -0.4 \  m

8 0
3 years ago
Predict the date of the next full moon.
lapo4ka [179]

Answer:

The 19th

Explanation:

going based off of the calandar, you just start from the 4 at the bottom and then just count up as you go through it agains starting back at the top.

4 0
3 years ago
Read 2 more answers
A 17Kg sitting on a shelf has a potential energy of 350J. How high is the shelf? Round your number to the nearest whole number
saul85 [17]

Answer:

{ \bf{potential \: energy = mass \times gravitation \times height}} \\ 350 = 17 \times 10 \times h \\ 350 = 170h \\ height = 2.06 \: metres

6 0
3 years ago
The tape in a videotape cassette has a total
xxMikexx [17]

Answer:

w=19.76 \ rad/s

Explanation:

<u>Circular Motion </u>

Suppose there is an object describing a circle of radius r around a fixed point. If the relation between the angle of rotation by the time taken is constant, then the angular speed is also constant. If that relation increases or decreases at a constant rate, the angular speed is given by:

w=w_o+\alpha \ t

Where \alpha is the angular acceleration and t is the time. If the object was instantly released from the circular path, it would have a tangent speed of:

\displaystyle v_t=w.r

We have two reels: one loaded with the tape to play and the other one empty and starting to fill with tape. They both rotate at different angular speeds, one is increasing and the other is decreasing as the tape goes from one to the other. We'll assume the tangent speed is constant for both (so the tape can play correctly). Let's call w_1 the angular speed of the loaded reel and w_2 that from the empty reel. We have

w_1=w_{o1}+\alpha_1 \ t

w_2=w_{o2}+\alpha_2 \ t

If r_f=35\ mm=0.035\ m is the radius of the reel when it's full of tape, the angular speed for the loaded reel is computed by

\displaystyle w_{01}=\frac{v_t}{r_f}

The tangent speed is computed by knowing the length of the tape and the time needed to fully play it.

t=1.8\ h=1.8*3600=6480\ sec

\displaystyle v_t=\frac{x}{t}=\frac{249\ m}{6480\ sec}=0.0384 \ m/s

\displaystyle w_{01}=\frac{0.0384}{0.035}=1,098 \ rad/s

If r_e=10\ mm=0.001\ m is the radius of the reel when it's empty, the angular speed for the empty reel is computed by

\displaystyle w_{02}=\frac{0.0384}{0.001}=38.426 \ rad/s

The full reel goes from w_{01} to w_{02} in 6480 seconds, so we can compute the angular acceleration:

\displaystyle \alpha_1=\frac{w_{02}-w_{01}}{6480}

\displaystyle \alpha_1=\frac{38.426-1.098}{6480}=0.00576 \ rad/sec^2

The empty reel goes from w_{02} to w_{01} in 6480 seconds, so we can compute the angular acceleration:

\displaystyle \alpha_2=\frac{1.098-38.426}{6480}=-0.00576 \ rad/sec^2

So the equations for both reels are

w_1=1.098+0.00576 \ t

w_2=38.426-0.00576 \ t

They will be the same when

1.098+0.00576 \ t=38.426-0.00576 \ t

Solving for t

\displaystyle t=\frac{38.426-1.098}{0.0115}

t=3240 \ sec

The common angular speed is

w_1=1.098+0.00576 \ 3240=19.76 \ rad/s

w_2=38.426-0.00576 \ 3240=19.76 \ rad/s

They both result in the same, as expected

\boxed{w=19.76 \ rad/s}

6 0
4 years ago
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