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andrey2020 [161]
3 years ago
7

In a standing wave, areas of destructive are the?

Physics
2 answers:
motikmotik3 years ago
8 0

Answer: the place where the wave hits

 ____

(          \ = wave

(            \

Alborosie3 years ago
4 0

antinodes

Hope this helps :)

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All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will
VikaD [51]

5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}

since v_y = 0 at the top of its trajectory. Plugging in the numbers,

t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}

8 0
3 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
Paul [167]
According to Newton, an object will only accelerate if there is a net or unbalanced forceacting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
6 0
3 years ago
Read 2 more answers
Convert planks constant in cgs system
dezoksy [38]

in cgs system, plank's constant= h=6.626 x10⁻²⁶ erg s

Value of Plank's constant in SI system= 6.626 x10⁻³⁴ Js

now 1 Joule= 10⁷ ergs

so h= 6.626 x10⁻³⁴ Js (10⁷ ergs/1J)

h=6.626 x10⁻²⁷ erg s

7 0
3 years ago
The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

      = 2.21074 x 10500

      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0
2 years ago
A woman is running around a playground while keeping an eye on her child who is on a swing set. The child is going back and fort
Nutka1998 [239]

Answer:

(a) 1500 m

(b) 2827.43m

Explanation:

Given that the time for one cycle of the swing is 1 s

The radius of the swing, R= 3.0m

The angle covered, \theta, by each swing is a quarter of the circle. i.e.

\Theta=\frac {\pi}{2}

Speed of running of women =5 m/s.

Time of running = 5 minutes= 5 x 60 secondes= 300 s.

(a) As distance= (speed) x (time)

So, the required distance= 5 x 300 m= 1500 m.

(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.

As arc length, l= \theta R, where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.

So, the distance covered by the child in 1 swing = \frac {\pi}{2}\times 3 m=\frac{3\pi}{2}m.

In 1 cycle, there are 2 swings, so distance covered in 1 cycle = 3 \pi m.

Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.

So, the total distance covered by the child

= 3\pi\times 300 m= 2827.43 m.

3 0
3 years ago
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