Zeros of this function are not real, this is because if we’re using the quadratic formula our discriminant has to be positive to produce any real number as a solution. In this case our discriminant is -4 using the formula B^2-4AC.
<h2>
Answer with explanation:</h2>
In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.
Given : Suppose the null hypothesis, , is: Darrell has enough money in his bank account to purchase a new television.
Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.
i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.
Probability of being defective is 14% = 14/100 = 7/50
P(Both defective) = 7/50 * 7/50 = 49/2500
Answer:
1 when -2<x<2
-1 when |x|>2
Step-by-step explanation:
Hope it helps
Answer:
Step-by-step explanation:
Using Bayes' theorem, we have:
is a conditional probability: the likelihood of event A occurring, given that B is true.
is also a conditional probability: the likelihood of event B occurring, given that A is true.
P(A) and P(B) are the marginal probabilities of observing A and B, independently of each other.
We solve thus:
=
=
=
=
= or %
Therefore, if an individual tests positive, it is more likely than not (1 - 33.2% = 66.8%) that they do not use the drug.