Question

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train travels at a faster rate in by what factor?
Train A is faster by factor of .20

Train A is faster by a factor of 1.01

Train b is faster by a factor of .20

Train b is faster by a factor of 1.01

Answer 1

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor  =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A  =$\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5  miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate  =1.01