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2 years ago

How to write 7.1 as a mixed fraction

Mathematics

2 answers:

DENIUS [597]2 years ago

6 0

7 1/10
this is the answer you are looking for, Hope this helps!:)

Solnce55 [7]2 years ago

3 0

Well the 7 is in the ones place so it becomes the whole and the 1 is in the tenths so it goes over 10
and your answer is 7 $\frac{1}{10}$

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|x-1| if x>1<br> how do you simplify this

JulsSmile [24]

Use the definition of absolute value.

$|x| = \begin{cases} x & \text{if } x \ge0 \\ -x & \text{if } x < 0 \end{cases}$

The absolute value is always non-negative. So if $x$ is already non-negative, $|x|=x$ is unchanged. But if $x$ is negative, then $|x|=-x$ because multiplying $x$ by -1 makes it positive.

Now, if $x>1$ , then by the definition of absolute value,

$x > 1 \implies x - 1 > 0 \implies \boxed{|x - 1| = x - 1}$

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1 year ago

Pls help me I don’t understand

ipn [44]

Answer:

m<PXQ Is Acute

m<QXN is Obtuse

Step-by-step explanation:

Acute Angles are lsss than 90⁰

Obtuse Angles are greater than 90⁰

Right angles are exactly 90⁰

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3 years ago

10. rhombus abcd has vertices at a(-2, 7), b(8, 7), c(2, -1), and d (-8, -1).

horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula $A=\frac{d_{1}d_{2}}{2}$ , where $d_{1}, d_{2}$ are the lengths of the diagonals.

By the distance formula,

$AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}$

So, the area is $\frac{(4\sqrt{5})(8\sqrt{5})}{2}=\boxed{80}$

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2 years ago

5. By using prime factorisation, determine if 324 and 588 are<br> perfect squares.

ad-work [718]

Step-by-step explanation:

first do prime factorization of 324= 2×2×3×3×3×3

= 2 square, 3 square,3 square

therefore 324 is a perfect square

Now,

prime factorization of 588=2×2×3×7×7

= 2 square,7 square ,3

therefore 588 is not a perfect square

3 0

2 years ago

32 and 2.56 what is the unit rate

Serggg [28]

12.5

I hope this helped.

5 0

2 years ago