Valence electrons in NH2Cl:
=1(5)*2(1)*1(7)
=14
So there are 14 valence electrons in NH2Cl
As each stick represents an valence electron pair.
And there are 14 valence electrons, so there can be 7 valence electron pairs.
And for 7 valence electron pairs, 7 sticks needed.
Answer: 149
Explanation:
Using the ideal gas equation; PV = nRT
P= Pressure = 0.910 atm, T= Temperature = ?
V= Volume = 4.0L R = Gas constant = 0.08206 L.atm/mol/K
n = number of moles = 0.297
Making 'T' the subject of the formular, we have;
T = P V/ n R = 0.910 x 4 / 0.297 x 0.08206
= 149
Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.
<h3>How do we calculate gained energy?</h3>
The amount of energy which is gained by any sample will be calculated as:
Q = mcΔT, where
Q = gained energy
m = mass of sample = 10g
c = specific heat of water = 4.18 J/g°C
ΔT = change in temperature = 18 - 13 = 5°C
On putting values we get
Q = (10)(4.18)(5)
Q = 209 Joules
Hence required amount of energy is 209 joules.
To know more about gained energy, visit the below link:
brainly.com/question/21704399
