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4 years ago

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Chemistry

1 answer:

Harrizon [31]4 years ago

4 0

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

Explanation:

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

$100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}$

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

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If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution

77julia77 [94]

Answer:

The molarity of the diluted HCl solution: M₂ = 0.045 M

Explanation:

To find- the molarity of the diluted HCl solution (M₂)

Given- For original HCl solution-

Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L (∵ 1L = 1000 mL)

Then this original solution is diluted to a volume of 2 L

Thus for the diluted HCl solution-

The Volume of the diluted HCl solution: V₂ = 2 L

So the Molarity of the diluted HCl solution (M₂) can be calculated by the dilution equation:

$M_{1}\times V_{1} = M_{2}\times V_{2}$

$\Rightarrow M_{2} = \frac{M_{1}\times V_{1}}{V_{2}}$

$\Rightarrow M_{2} = \frac{1.5 M\times 0.06 L}{2 L} = 0.045 M$

Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M

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3 years ago

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The solubility of Ar in water at 25 °C is 1.6 ⋅ 10-3 M when the pressure of the Ar above the solution is 1.0 atm. The solubility

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Answer:

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Explanation:

Henry's law:

Sg = (Kh)*(Pg)

∴ Sg: gas solubility (mol/L)

∴ Kh: Henry's constant ⇒ Kh Ar = 1.5 E-3 mol/atm.L.....from literature

∴ Pg: Partial pressure of gas on solution (atm)

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Answer:

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b) 9424797000000 liters

c) 9424797000000 kg

Explanation

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Area Cylinder = π r^2 = 3,141599* (1000m)^2 = 3141599 m2

a) Volume Cylinder= area x Height=3141599 m2* 3000 m= 9424797000 m3

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9424797000 kg

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