Moles XeF6 = 10.0g/ 245.28 g/ mol=0.0408
The ratio between F2 and XeF6 is 3:1
Moles F2 required = 3 x 0.0408=0.122
Mass F2 = 0.122 mol x 37.9968 g/ mol=4.64g

6 0

3 years ago

12. The most common factors that cause chemical reactions to occur are all the following except

ruslelena [56]

Transfer of electrons

6 0

4 years ago

How many calories are required to convert 17 g of ice at 0.0Â°C to liquid water at 32.0Â°C? The heat of fusion of water is 80. c

Mazyrski [523]

Answer : The heat required is, 1904 calories.

Explanation :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(32.0^oC)$

The expression used will be:

$\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

m = mass of ice = 17 g

$c_{p,l}$ = specific heat of liquid water = $1cal/g^oC$

$\Delta H_{fusion}$ = enthalpy change for fusion = $80.0cal/g$

Now put all the given values in the above expression, we get:

$\Delta H=17g\times 80.0cal/g+[17g\times 1cal/g^oC\times (32.0-0)^oC]$

$\Delta H=1904cal$

Therefore, the heat required is, 1904 calories.

3 0

4 years ago

Balance the following oxidation-reduction reaction: Fe(s)+Na+(aq)→Fe2+(aq)+Na(s) Express the coefficients as integers separated

aliina [53]

Answer:

The answer to your question is: 1, 2, 1, 2

Explanation:

1 Fe(s) + 2 Na⁺(aq) → 1 Fe²⁺(aq) + 2 Na(s)

Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases

Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces

1 x ( 1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of

2 x ( 2Na⁺ ⇒ 2 Na⁰ ) electrons

6 0

3 years ago