Answer:
3.5 hours
Step-by-step explanation:
Speed of train X=30 mph
Speed of train Y=40 mph
Relative speed When the two trains travelling in same direction
Relative speed=40-30=10 mph
Total distance =25+10=35 miles
We have to find the time when train Y is 10 miles ahead of train X.
We know that
Time=
Using the formula
Then, we get
Time=
Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.
This is one of the special right triangles known as a 30, 60, 90 triangle. (Characterized by its angles)
In these triangles, the shortest leg is HALF the length of the hypotenuse.
The longest leg is (√3) times the length of the short leg.
Therefore, the shortest leg is 20, and the longest leg is 20(√3)
FINAL ANSWER:
SHORT LEG: 20 units
LONG LEG: 20√3 units
Answer: The coordinate are
( 5 , 2.5 )
Distance = 5
Step-by-step explanation:
The coordinates of the rest stop will be the mid point between the high school is at point (3, 4) and the stadium in Columbus at point (7, 1).
Mid point = (X1 +X2)/2 , (Y1+Y2)/2
(3+7)/2 , (4+1)/2 = ( 5 , 2.5 )
The approximate distance between the high school and the stadium will be
D^2 = (7-3)^2 +( 4-1)^2
Where D = distance
D^2 = 4^2 + 3^2
D = 5
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
