Find the first,fourth,and tenth terms of the arithmetic sequence described by the given rule. A(n) = 12+(n-1)(3)
1 answer:
The answers are: the first term: 21 the fourth term: 22 the tenth term: 39 <span>A(n) = 12+(n - 1)(3) n = 1 A(1) = 12 + (1 - 1)(3) = 12 + 0*3 = 12 + 0 = 12 n = 4 </span>A(4) = 12 + (4 - 1)(3) = 12 + 3*3 = 12 + 9 = 21 n = 10 A(10) = 12 + (10 - 1)(3) = 12 + 9*3 = 12 + 27 = 39
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