Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
Answer:
The answer is 58.09
Step-by-step explanation:
To get the final position, you add the displacement to the initial position.
Final position = 25.89 + 32.2
Final position = 58.09metres
Answer:
7x^2 -5x + 4
Step-by-step explanation:
5x^2 – 6x+2
- (-2x^2 - x - 2)
We got 5x^2 - (-2x^2) = 5x^2 + 2x^2 = 7x^2
-6x - (-x) = -6x + x = -5x
2 - (-2) = 2+2 = 4
So the equation would be 7x^2 -5x + 4
Hope this help :3
Answer:
.26 = 26% hope this helps! :)
Step-by-step explanation:
.26
100 = 1.00
26 = .26
you just move the decimal point over 2
120/20=6 so it’s six dollars a ticket
1=$6
3=$18
4=$24
5=$30
6=$36
n=6n
