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2 years ago

How any is? 8m + 27 = 2m - 3 with procedure and testing

Mathematics

2 answers:

Bezzdna [24]2 years ago

4 0

Step by step hope this helps:)

givi [52]2 years ago

3 0

8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.

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2 years ago

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3 years ago

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3 years ago

A flush in the card game of poker occurs if a player gets five cards that are all the same suit (clubs, diamonds, hearts, or

Artyom0805 [142]

Answer:

The probability is 0.000495

Step-by-step explanation:

As per the question:

Total no. of cards in a deck = 52

No. of spades in a deck = 13

Now, we have to select 5 cards in a deck such that they belong to the same suit, i.e., spades.

The no. of ways of selecting 5 cards from a deck = $^{52}C_{5} = \frac{52!}{5!(52 - 5)!} = \frac{52!}{5!47!}$

The no. of ways of selecting 5 cards from 13 spade cards = $^{13}C_{5} = \frac{13!}{5!(13 - 5)!} = \frac{13!}{5!8!}$

Now,

Probability that the selected 5 cards are all spades, P(E) = $\frac{No.\ of\ ways\ of\ selecting\ 5\ cards\ from\ 13\ spade\ cards}{No.\ of\ ways\ of\ selecting\ 5\ cards\ from\ a\ deck}$

P(E) = $\frac{^{13}C_{5}}{^{52}C_{5}}$

P(E) = $\frac{\frac{13!}{5!8!}}{\frac{52!}{5!52!}}$

P(E) = $\frac{\frac{13\times 12\times 11\tiems 10\times 9}{5\times 4\times 3\times 2\times 1}}{\frac{52\times 51\times 50\times 49\times 48}{5\times 4\times 3\times 2\times 1}}$

P(E) = $\frac{13\times 12\times 11\tiems 10\times 9}{52\times 51\times 50\times 49\times 48} = 4.95\times 10^{- 4} = 0.000495$

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2 years ago