The average atomic mass of copper is 63.55 amu. If the only two isotopes of copper have masses of 62.94 amu and 64.93 amu, what
1 answer:
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Answer:
John Dalton's Atomic Model Below ⬇
Explanation:
Answer: (a) The solubility of CuCl in pure water is .
(b) The solubility of CuCl in 0.1 M NaCl is .
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.
Initial: 0 0
Change: +x +x
Equilibm: x x
And, equilibrium expression is as follows.
x =
Hence, the solubility of CuCl in pure water is .
(b) When NaCl is 0.1 M,
,
,
Net equation:
= 0.1044
So for,
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' =
0.1044 =
x =
Therefore, the solubility of CuCl in 0.1 M NaCl is .
The percent yield of copper hydroxide is 84%
<h3>Stoichiometry</h3>From the question, we are to determine the percent yield of copper hydroxide
First, we will determine the theoretical mass
From the given balanced chemical equation, we have
Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃
This means,
1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide
Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide
The theoretical number of moles of copper hydroxide that is produced is 0.05 mole
Now, for the theoretical mass
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of copper hydroxide = 97.56 g/mol
Then,
Theoretical mass = 0.05 × 97.56
Theoretical mass of copper of hydroxide produced is = 4.878 g
Now, for the percent yield of copper hydroxide
Percent yield is given by the formula,
Then,
Hence, the percent yield of copper hydroxide is 84%.
Learn more on Stoichiometry here: brainly.com/question/9372758