Answer:
Empirical formula = CH2O
Molecular formula = C6H12O6
Explanation:
According to this question, a compound is said to contain the following: 48.38g Carbon, 8.12g H, and 53.5g O.
First, we divide each mass value by its molar mass to convert to a mole value;
C = 48.38g ÷ 12g/mol = 4.03mol
H = 8.12g ÷ 1g/mol = 8.12mol
O = 53.5g ÷ 16g/mol = 3.34mol
Next, we divide each mole value by the lowest value (3.34mol)
C = 4.03mol ÷ 3.34 = 1.21
H = 8.12mol ÷ 3.34 = 2.43
O = 3.34mol ÷ 3.34 = 1
Approximately, the empirical ratio of CHO = 1:2:1, hence, the empirical formula is CH2O.
2. If the molar mass of the compound was determined to be 180.15 g/mol.
C = 12, H = 1, O = 16
(CH2O)n = 180.15
{12 + 1(2) + 16}n = 180.15
(12 + 2 + 16)n = 180.15
(30)n = 180.15
n = 180.15 ÷ 30
n = 6.005
Hence, (CH2O)n = (CH2O)6
Molecular formula = C6H12O6
