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Sergio [31]
3 years ago
8

What gets released back into the air when humans and animals breathe ? What is this process called?

Chemistry
2 answers:
expeople1 [14]3 years ago
6 0

Answer:

Respiration is the process humans and animals breathe c02 out

Komok [63]3 years ago
3 0

Answer:

CO2 is released into the air when we breathe

The process is called respiration

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The following data were measured for the reaction BF3(g)+NH3(g)→F3BNH3(g): Experiment [BF3](M) [NH3](M) Initial Rate (M/s) 1 0.2
Rama09 [41]

Answer:

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

Explanation:

The rate law of a chemical reaction is given by

-r_{A}=k\times[BF_3]^{\alpha}\times[NH_3]^{\beta}

This law can be written for any experiment, and making the quotient between those expressions the reaction orders can be found

Between experiments 1 and 2  

\frac{-r_{A1}}{{-r}_{A2}}=\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)^\beta

Then the expression for the calculation of \beta

\beta=\frac{ln\frac{-r_{A1}}{-r_{A2}}}{ln\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)}=\frac{ln\frac{0.2130}{0.1065}}{ln\left(\frac{0.250}{0.125}\right)}

Resolving  

\beta=1

Doing the same between experiments 3 and 4 the expression for \alpha is

\alpha=\frac{ln\frac{-r_{A3}}{-r_{A4}}}{ln\left(\frac{\left[BF_3\right]_3}{\left[BF_3\right]_4}\right)}=\frac{ln\frac{0.0682}{0.1193}}{ln\left(\frac{0.200}{0.350}\right)}

Resolving  

\alpha=1

This means that the rate law for this reaction is  

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

5 0
3 years ago
How are lysosomes similar to vacuoles?
lawyer [7]
Lysosomes are simlar to vacuoles by them working together basically. they both are enclosed organelle compartments within cell. vacuoles store the food waste, bacteria, etc. while the lysosomes breaks them down
6 0
3 years ago
Calculate the oxidation number for carbon in CH4
Maksim231197 [3]

Answer:

+4

Explanation:

Oxidation number of neutral compound is 0

Oxidation number of hydrogen in methane is -1

C + (-1×4) = 0

C - 4 = 0

C = 4

8 0
2 years ago
Difference between dipole dipole and hydrogen bonding
riadik2000 [5.3K]

Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.

<h3>What is bonding in molecules?</h3>

Bonding is a type of attraction force which is present between the different atoms or elements of any substance.

  • Dipole dipole attraction force is a weak force as compared to the hydrogen bonding and present between any two oppositely charged atoms.
  • Hydrogen bond is present between the hydrogen atom and more electronegative atoms like O, S, N and F.

Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.

To know more about dipole-dipole force, visit the below link:
brainly.com/question/24197168

#SPJ4

8 0
2 years ago
A student wants to remove the salt from a mixture of sand and salt in order to get only pure sand. He adds water to the mixture.
raketka [301]

Answer:

Here is one way: Add water to the mixture. Only the sugar dissolves. This is a physical change.

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

5 0
3 years ago
Read 2 more answers
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