Atoms of the element beryllium would most likely behave similar to the way _______ behaves?
2 answers:
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Answer:
, Kp = 0.08967
, Kp = 2.3×10³⁰
Explanation:
The relation between Kp and Kc is given below:
Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:
Given: Kc = 2.2
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2+1) = -1
Thus, Kp is:
<u>Kp = 0.08967 </u>
For the second equilibrium reaction:
Given: Kc = 2.3×10³⁰
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2) = 0
Thus, Kp is:
<u>Kp = 2.3×10³⁰</u>