Answer:
(C)
Step-by-step explanation:
It is given that Point Z is equidistant from the vertices of ΔTUV, therefore ZT=ZU=ZV.
Now, from ΔBTZ and ΔBUZ, we have
ZT=ZU (Given)
BZ=ZB (common)
therefore, by RHS rule of congruency,
ΔBTZ≅ΔBUZ
Thus, by corresponding parts of congruent triangles, we have
∠BTZ=∠BUZ
Thus, option C is correct.
Also, it is not necessary that TA=TB and AZ=BZ because there is no information given regarding these equalities.