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KATRIN_1 [288]
3 years ago
15

Find the solutions to the equation by completing the square.

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

Step-by-step explanation:

hello :

x² - 6x = 7

x² - 6x+9-9___= 7

(x - 3 )²= __16_

x - 3= +/-_4__

x-3=4__and x-3 =_-4_

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Ella has a box of chocolate candies. She gives 1/3 of the candies to her sister, 4 to her brother, and eats the remaining 12 can
tatyana61 [14]

Answer:

24 candies originally

Step-by-step explanation:

Add the 4 to how many you had left, then think about that number, 16, and what goes into 16 evenly 2 times? 8 and originally she gave away 1/3 of the box and if you were to add another 8 to the box it would be 24 divided by 1/3, -,-4,= 12.

3 0
3 years ago
At Morton Williams this week, avocados cost 4 for $5. what is the price for one avocado? If the regular price of one avocado is
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2 years ago
Plz, help me I will give you a brainlist and Extra points. If you help me.
stiv31 [10]

Answer:

B) (4/9 x 20)-3

8 0
3 years ago
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
Find the constant of variation for the relationship shown in the following table:
EastWind [94]

In order to get the constant of variation, you can either make a linear equation that relates x and y in which the slope is the constant of variation

LINEARIZING

x = 3y

the slope of the equation is 3 and therefore the constant of variation is 3

 

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5 0
2 years ago
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