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cluponka [151]
3 years ago
14

What is the equation of a circle whose center is at (-2, 1) and radius is 2.2?

Mathematics
1 answer:
Lena [83]3 years ago
3 0
C is the correct answer
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Sami cuts out a rectangle that has a perimeter of 48 inches and a length of 13 inches.
ddd [48]

Answer:

Width is 11 inches

Step-by-step explanation:

I am not sure what the question is.  I think you might be looking for the width length.  The perimeter is the distance around a rectangle.  If the whole distance around is 48.  We have 2 lengths and 2 widths.  They tell us that the length is 13.  We have two lengths so the lengths add up to 26.  We can subtract that from 48 and that leaves us with 22 (48-26)  This is the total for the 2 widths.  Since the 2 widths are the same length we divide that number by 2 to get 11.

11 + 11+ 13 + 13 = 48

4 0
2 years ago
A school's playground, measuring 33 metres, 43 metres, 50 metres and 25 metres, is enclosed by a chain link fence. How many metr
SVETLANKA909090 [29]
Isn’t it just 151 metres?

33+43+50+25=151
4 0
3 years ago
Simplify the algebraic expression <br> 3/4(4x-8y)
kompoz [17]

Answer:

3x-6y

Step-by-step explanation:

3/4(4x-8y)

3/4×(4x-8y)

3/4×4(x-2y)

3×1(x-2y)

3x-6y

6 0
2 years ago
Helppppppppp i need an answer to this<br> math problem <br> attached file below
mestny [16]
The graphs of f and g intersect at x = 1, not x = -1.

g(x) is greater than f(x) for x < 1.

g(x) cannot be less than 1, as the graph flattens out at y = 1.

Based on the information given by the graph, the answer is "As the value of x increases, the value of g(x) will eventually exceed the value of f(x)".
7 0
3 years ago
If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb
iren [92.7K]

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

6 0
3 years ago
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