Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:
this is equivalent to:
thus, we can conclude that
x= 3.
Answer:
<em>B is the correct answer</em>, The first choice (which you chose) is the incorrect answer.
Step-by-step explanation:
Answer:
x 
9
Step-by-step explanation: i took a quiz with this on it
Answer:
(C) reflection of f(x) = 5x² across the x-axis and translated down 2 units
Answer: 1,2,3, and 5
Step-by-step explanation:
The isometries that preserve a shapes angles and line segments making the pre image congruent to the (post) image are :
Reflections, rotations, translations
These are rigid transformations. Think of your ruler. If you flip it, slide it, or rotate it around, did the ruler change shape? No. Just positions.
If you dilate something, you are either making it larger or smaller, therefore changing the size of the shape.
Anything that has dilation in its transformation does not have congruent shapes.
