Question

The function V=25000\left(0.82\right)^tV=25000(0.82) t models the depreciation of the value of a new car that originally cost $\text{25,000}25,000. VV represents the value of the car and tt represents the time in years from the time the car was purchased. What is the value of the car after 6 years?

Answer 1

Answer:

V = 7,600.17

Step-by-step explanation:

Given:

V=25000(0.82)^t

Where,

V = value of the car

t = time in years

Find V when t = 6

V = 25,000(0.82)^t

= 25,000(0.82)^6

= 25,000(0.304006671424)

= 7,600.1667856

Approximately

V = 7,600.17