The function V=25000\left(0.82\right)^tV=25000(0.82) t models the depreciation of the value of a new car that originally cost $\
text{25,000}25,000. VV represents the value of the car and tt represents the time in years from the time the car was purchased. What is the value of the car after 6 years?
Now the formula for the area of a circle is: πr². So we take 3 and just put it into the equation. π·3²=28.27. This is the area of the circle. Now the rate of change I think would just be the difference between the radius and the area of the circle so 28.27-3=25.27.
