Sam had $7.55 he then gave $4.46 to his friend. How much money does same have left?

Mathematics

1 answer:

Nana76 [90]3 years ago

7 0

answer:

$3.09 left over

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A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x)=-2x^2+20x+48h(x)=

Ad libitum [116K]

the maximum height is the y-value of the vertex.

h(x) = -2x² + 20x + 48

$x = \frac{-b}{2a} = \frac{-20}{2(-2)} = \frac{-20}{-4} = 5$

h(5) = -2(5)² + 20(5) + 48

= -50 + 100 + 48

= 50 + 48

= 98

Answer: 98 meters

8 0

3 years ago

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$