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3 years ago

What is .25 written in its simplest fraction form? A. 2/5 B. 4/1 C. 1/4 D. 100/25

2 answers:

5 0

0.25 = 25/100

to simplify 25/100, divide 25 from both the numerator and denominator.

25/25 = 1

100/25 = 4

1/4 is the simplest form

C. 1/4 is your answer

hope this helps

nasty-shy [4]3 years ago

3 0

C 1/4 just like money if you have 1 quarter it is 25 cents so you have 1/4 quarters. Can u mark me as the brainiest answer thnx

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Three students have started a fence-painting business. Working together, Pragnesh and Qazi can paint the fence in 12 hours. Simi

Mila [183]

Step-by-step explanation:

P and Q can do the whole work in 12 hours.

so, in 1 hour they can do 1/12.

P and R can do in 1 hour 1/15.

Q and R can do in 1 hour 1/20.

mathematically that looks like

P + Q = 1/12

P + R = 1/15

Q + R = 1/20

P + Q + R = 1/x

together they can do 1/x of the work in 1 hour.

it will take them x hours, if all 3 worked together.

from the first equation we get

P = 1/12 - Q

that gives us in the second equation

1/12 - Q + R = 1/15

R = 1/15 - 1/12 + Q = 4/60 - 5/60 + Q = Q - 1/60

but from the 3rd equation we get also

R = 1/20 - Q

so,

Q - 1/60 = 1/20 - Q

2Q = 1/20 + 1/60 = 3/60 + 1/60 = 4/60

Q = 2/60 = 1/30

R = Q - 1/60 = 2/60 - 1/60 = 1/60

P = 1/12 - Q = 1/12 - 2/60 = 5/60 - 2/60 = 3/60 = 1/20

so, we get for the sum :

P + Q + R = 3/60 + 2/60 + 1/60 = 6/60 = 1/10

that means in 1 hour they can do together 1/10 of the work.

so, together they will need 10 hours to paint the fence.

3 0

2 years ago

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

$P(B) = \frac{8}{12}$

$P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}$

<h3><u>Find </u><u> P(R | B)</u></h3><h3> $P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}$ </h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

$\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%$

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0

3 years ago

Round the number to the place indicated.<br> Round to the nearest tenth: 1.4511

Evgen [1.6K]

1.500 since 45 rounds to 50

8 0

3 years ago

Help me please don't know

dem82 [27]

1. 5 x 5
2. 7 x 28
3. 90 divided by 70
4. 40 divided by 5.
Hope this helps. #I'm11

8 0

4 years ago

in a yaz game, Gina won 3 games, lost 5, later won 6 and finally lost 4, what was the balance of the game?

Andreas93 [3]

Answer:

Step-by-step explanation: 3-5=-2+6=4-4=0

8 0

3 years ago