A tub filled with 50 quarts of water empties at a rate of 2.5 quarts per minute. let w = quarts of water left in the tub and t =
2 answers:
This is a linear relationship. The slope-intercept form of the linear equation is:
Where,
- m is the rate of change (positive if increasing rate and negative if decreasing rate)
- c is the y intercept, or the initial value
<u><em>Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)</em></u>
<u><em>Initial value is 50 quarts, so c is 50.</em></u>
Plugging in the values we get .
Changing variables to w instead of y and t instead of x, gives us,
. Where w is warts of water left in the tub and t is the time in minutes.
There is no viable solution when t=30 because at t=20, w=0 (). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.
ANSWER:
Modelling equation:
When , there is no VIABLE solution
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Step-by-step explanation:
Method A
1) Method A: Let 2 be the starting point and -2, the finishing one. Counting between 2 and -2, we can count a distance of 4 units. That's the simplest way, but not convenient to great numbers on the Number Line.
Method B:
There is no such thing as a negative distance, as a physical quantity. So this is the reason why we need to compute the absolute value of two numbers, which is simply what was done on Method B.
|2-(-2)|=|4|=4
As we are dealing with absolute values, the order is not relevant after all, the result remains the same. Take a look:
|-2-2|=|-4|=4
That's why the greater (2) or the lesser number (-2) can be the subtrahend (in bold within the brackets.
Answer:
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